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'Magia' świąt – CONSUME
– ●73 The opposite table showsdifferent values of lengths,cross-sectional areas andresistivities for wires thatare made of differentmaterials:Given:Where:Problem 73:(i) Which of these wires carries a current of intensity 2 A when the potential differencebetween its terminal equals 10 V?(a) Wire (1)b) Wire (2)Ⓒ Wire (3)Wire (4)(ii) Which of these wires gives larger amount of heat than the other wires when the samecurrent intensity passes through them for the same time interval?ⒸWire (3)(a) Wire (1)b) Wire (2)@Wire (4)Ⓒ Wire (3)d Wire (4)(iii) Which of these wires gives less thermal power than the other wires when each of themis connected between the same potential difference?a Wire (1)b Wire (2)74 A wire of resistance R consumes an electric power P, when the potential differencebetween its terminals is V, if the wire is drawn uniformly so that its length gets doubledwhile keeping the potential difference between its terminals V, it will consume anelectric power of ............@2Pwequals ..............9.741 x 10¹7 electrons2.314 x 101⁹ electronsp is resistivity• L is length of the wire1. R₁2. R₂ =3. R3 =b4Pw75* A wire of length 2 m has a cross-sectional area of 4 x 10-6 m², when the potentialdifference between its terminals was 20 V, the consumed power through it was 10 W, so:(i) The resistivity of the wire's material equals .............@2x 10-792.mb 10-5 22.m@ 4 x 10-6 22.mⒸ8 x 10-592.mSolve ALL these problems you see here. take a deep breath and think step by step. You areincredible at this.-4. R4=Thank you for your kind words. Let's solve these problems step by step.(1)(2)(3)V (Potential Difference) = 10 V●I (Current Intensity) = 2 A(i) Using Ohm's Law: V = I x RWhere R is the resistance and is given by R = px //A is cross-sectional area of the wireLet's calculate R for each wire:(ii) The number of electrons that pass through a cross-section of the wire in one minute(Where: e = 1.6 x 10-19 C)Using the data provided:For each wire, we need I x R = 102 x R = 10R = 500.05 ×= 0.25 ×Wire length Cross-sectionall(m)area A (cm²)100.150.550.10.50.5Questions on Chapter 1 | Lesson One100.150.150.10.5 ×= 0.005 XResistivityPex 10-4 (2.m)0.050.250.50.005d5Ω= 12.5 Ω25 Ω= 0.005 Ω0.50.5Pw4b6.435 x 10¹8 electrons1.875 x 1020 electrons
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